topic: integral calculus, help me to integrate this pleasee, Integral of (2 + 5/x)^2 dx
\[\int\limits (2 + 5/x)^2 dx\]
@iGreen @MARC_ @nikvist
@phi
@ilo
@Ilovecake
simplest is just expand the brackets and do each term
so it will become (4+ 25/x^2 ?
@Ilovecake
Yes
then
no no no
how? @IrishBoy123
(2+ 5/x) times (2+ 5/x)
ah , what should i do next
do that expansion then integrate each bit separately.
i will multiply it each by piece?
@IrishBoy123
yep post yr answer here
( 4 + 10/x+10/x +4)
@IrishBoy123
is the original expression \[ \left(2 + \frac{5}{x}\right)^2 \]
yes
after squaring did you get \[ 4 + \frac{25}{x^2} + \frac{20}{x} \]
yes then what will i do
write the problem as \[ 4\int \ dx + 25\int x^{-2} \ dx + 20 \int \frac{dx}{x} \]
I assume you can do some of those integrals ?
i dont know what to do next
are you saying you don't know how to do \[ 4 \int dx \] ?
yes
the integral of dx is x based on this question, they expect you to know quite a bit of integral calculus, and integral of dx is the first baby step, which means you have to learn a lot of stuff to do this problem. And it's very hard to learn or teach calculus typing into this box. Maybe watch Khan's videos https://www.khanacademy.org/math/integral-calculus/indefinite-definite-integrals/indefinite_integrals/v/antiderivatives-and-indefinite-integrals
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