How many moles of N2 are essential for generating 0.08 moles of Li3N in the given reaction?
6Li + N2 2Li3N

0.013 moles

0.04 moles

0.08 moles

0.16 moles

0.48 moles

Question

How many moles of N2 are essential for generating 0.08 moles of Li3N in the given reaction?
6Li + N2   2Li3N

0.013 moles

0.04 moles

0.08 moles

0.16 moles

0.48 moles

anonymous · Answer

I am not sure on how to find this.

jfraser · Answer

the balanced reaction will give you the molar ratios you need.

Use the reaction like a ratio

jfraser · Answer

$2$ moles of $Li_3N$ will be produced from $1$ mole of $N_2$

anonymous · Answer

So, do you have to find the Molar masses of each of the elements?

jfraser · Answer

you're not asked about mass, so you don't need it here

jfraser · Answer

so the molar ratio of $\frac{Li_3N}{N_2}$ is $\frac{2}{1}$

jfraser · Answer

the molar ratio MUST BE maintained, so if you replace the moles of $Li_3N$ with 0.08, what does the bottom number turn into in order to keep the ratio the same?

anonymous · Answer

0.04?

jfraser · Answer

it is

anonymous · Answer

So that would be my answer, correct?

jfraser · Answer

yes

anonymous · Answer

Thank you!

anonymous · Answer

I have another question.

anonymous · Answer

I am not sure if this would be the close to the one posted.

anonymous · Answer

How many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (CH3OH)?
2CH3OH + 3O2   2CO2 + 4H2O
-0.877 moles
-0.997 moles
-1.330 moles
-1.995 moles
-2.660 moles

jfraser · Answer

use the same method.

Find the mole ratio from the balanced equation, and find the number of unknown moles that makes your ratio still true