How many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (CH3OH)?
2CH3OH + 3O2 2CO2 + 4H2O

-0.877 moles

-0.997 moles

-1.330 moles

-1.995 moles

-2.660 moles

Question

How many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (CH3OH)?
2CH3OH + 3O2   2CO2 + 4H2O

-0.877 moles

-0.997 moles

-1.330 moles

-1.995 moles

-2.660 moles

anonymous · Answer

@amistre64

anonymous · Answer

Those arent negatives

anonymous · Answer

They are like ABCD.

anonymous · Answer

Methanol reacts with oxygen in a 2:3 ratio. Set it up like this:$$\color{green}{\dfrac{2}{3} = \dfrac{1.33}{x}}$$ Solve for x.

anonymous · Answer

@ghuczek you can cross multiply and devide correct?

jfraser · Answer

use the same method as your last problem,  but now the numbers aren't so nice and round anymore