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first equation times -2 and add them
what exactly does that mean?
multiply every term in the first equation times 2 (that is what I mean by "multiply the first equation times -2") after doing so, add the equations together.
so like this:
3 times -2 - 2y = 6?
\(\large\color{black}{ \displaystyle \color{red}{(}3x - 2y = 6\color{red}{)\times (-2)} }\) \(\large\color{black}{ \displaystyle \color{red}{ (-2)}3x - \color{red}{ (-2)}2y = \color{red}{ (-2)}6 }\) \(\large\color{black}{ \displaystyle -6x +4y = -12 }\)
this is how I multiply the equation times -2, I take each term in it and multiply times -2.
is this making some sense ?
ohhhhhh
yeah it makes sense now
yes, so your system of equations NOW, is: \(\large\color{blue}{ \displaystyle -6x +4y = -12 }\) \(\large\color{black}{ \displaystyle 6x - 4y = 14 }\) (In blue I posted your new 1st equation, that results after multiplying it times -2)
Now, do elimination (add these equations together)
okay this may take a min
take your time
i got 0x - 0y = 2
yes, that means that you got 0=2
Is it correct that THIS is what adding the equations together leaves you with?
yes
i think
so would the answer be
c? idk :/
well, if adding the equations (the elimination) gives you something that is not true under any circumstances.... then ?
ohhhh so no solutions
?
yes
no solution, is correct.
thank you!
Or think of it this way
When you plug in your "x" and "y" into the equation (into 0=2) you still get 0=2, since you aren't really plugging anything in (why? because x and y are not present in the equation) and that means that regardless of what value you choose for x and for y, the statement (statement 0=2) will never be true.
and that means that since there are no values of x and y that satisfy the statement 0=2, therefore there is no solution for x and for y.
ohhhhhhhhh!! that actually makes a lot of sense. thank you
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