How do you find the cot θ if csc θ = square root of five divided by two and tan θ > 0.
do you want to use Pythagorean identities or do you want to use a drawing.
Pythagorean identities please
well then we know the following: \[\sin^2(\theta)+\cos^2(\theta)=1 \\ 1+\cot^2(\theta)=\csc^2(\theta) \\ \tan^2(\theta)+1=\sec^2(\theta)\]
which equation I just listed do you think would be most helpful here
the second
exactly now let's keep in mind this: if tan is pos then cot is pos if tan is neg then cot is neg here we are given that tan>0 which means tan is pos
so we already know what sign the answer will have
now we need to replace csc(theta) with sqrt(5)/2
\[1+\cot^2(\theta)=(\frac{\sqrt{5}}{2})^2 \]
can you simplify the right hand side before we continue
yah
so once you do that you will solve that equation like you would if you were solving the following for x: \[1+x^2=(\frac{\sqrt{5}}{2})^2 \\ x^2=(\frac{\sqrt{5}}{2})^2-1 \] you would then take square root of both sides and decide which sign to use
so the right side would be 5/4
yah so you have \[1+\cot^2(\theta)=\frac{5}{4}\]
then how would you continue?
just like I did above
subtract 1 on both sides
then take the square root of both sides and decide which sign to use
ok one second
\[\cot \theta=\sqrt{5/4-1}\]
right you chose the right sign since cot is positive
now simplify your answer
it would be \[1/2\]
yep yep
Thank you XD
Join our real-time social learning platform and learn together with your friends!