Question

Write the standard form of the line that passes through the point (-2, 4) and is parallel to x - 2y = 6

Answer 1

change x - 2y = 6
to the form y = mx + b

Answer 2

one useful property of parallel lines is that they have the same equation, but differ only by a constant

Answer 3

in other words:

ax + by = c
and
ax + by = k

are parallel lines

Answer 4

y=1/2x−3

Answer 5

So now what?

Answer 6

@amistre64

Answer 7

x - 2y = 6 is the stated line

x - 2y = k is parallel to it, and it must satisfy the point (-2,4), so what is k when x=-2 and y=4?

Answer 8

−x+2y=−6 is the line in standard form, but how do I find the line parallel?

Answer 9

standard form does not have a negative coefficient on the x variable .....

Answer 10

x - 2y = 6 is the stated line

x - 2y = k is parallel to it, and it must satisfy the point (-2,4),

so what is k when x=-2 and y=4?

Answer 11

-10

Answer 12

So now what? @amistre64

Answer 13

then let k = -10 and we have the solution

x - 2y = -10 is parallel to x - 2y = 6, and it contains the point (-2,4)

Answer 14

and, its in standard form: ax + by = c, a >=0

Answer 15

Thanks so much!

Answer 16

god luck