Question

Help??

Answer 1

HI!!

Answer 2

What do you need help on?

Answer 3

the first denominator factors as \((n+4)(n2)\) so that is the common denominator you can use

Answer 4

oops i mean it factors as \((n+4)(n+2)\)

Answer 5

multiply the second term by \(\frac{n+2}{n+2}\) then the denominators will be the same and you can subtract in the numerator

Answer 6

don't factor it
the numerator will be
\[n^2+3n+2-2n^2-4n\]

Answer 7

combine like terms

Answer 8

@misty1212

Answer 9

no!

Answer 10

it is a common mistake

Answer 11

\[n^2+3n+2-2n^2-4n=\color{red}-n^2-n+2\]