If I have a 1x1x1 cube. How can I make it so it has twice the surface area?
I think 6
well, the surface Area of a cube the dimensions of which are 1, 1, 1 is ?
There are 6 same faces, 1 by 1 each. So if each face has area of 1 (meter squared), then all of these 6 faces added would give you the (entire surface) area of ?
6
yes, the surface area of a cube whose side (each one) is 1, is 6.
so how do you make it so it is twice that?
Now, how did we obtain this surface area (once again) ? (I will denote my side as "s" ) \(\large\color{black}{ \displaystyle {\rm A_{~surface~of~a~cube}}~=~6s^2 }\) do you understand this formula?
(each face is s^2, and there are 6 of these faces )
yes or no ?
yes, so to make it so the surface area is twice as much you square it?
so you have the following for your surface area: \(\large\color{black}{ \displaystyle {\rm A_{~surface~of~a~cube}}~=~6(1)^2 }\) which gave you that A=6
but, we need to go backwards. We want to know how long should each side should be to get a surface area of 12.
\(\large\color{black}{ \displaystyle {\rm 12}~=~6s^2 }\)
Solve for s (and disregard any negative solution if you get it)
so 12/6=2 so \[\sqrt{2}=s ^{2}\]
you mean \(\large\color{black}{ \displaystyle s=\sqrt{2} }\) ?
yea sorry
it is alright, as long as you get it (which you apparently do).
So, to have a surface area of 12 (which is twice more than the surface of 6), you would need each side to be \(\large\color{black}{ \displaystyle \sqrt{2} }\) units long
any questions about this ?
no, thank you for your help
yw
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