cscx cotx(1-cos^2x)=_____x Fill in the blank
try expanding each expression: cscx = ? (1/sinx, right?) cotx = ? (1/tanx, right) 1-cos^2x = ? (sin^2x, right?) Then see how it goes from there.
im thinking ... csc^2x
Let's see: cotx = 1/tanx = cosx/sinx, then all it looks like 1/sinx * cos x/sinx * sin^2x Which simplifies to cos(x)
so final is cscx cotx(1-cos^2x)=cosx
Yes.
thank you
do you think you could help me with another?
Sure, go ahead.
@luffingsails cos9/2=+-sqrt1+cosa/2 for all values of a T/F
Looking. One sec.
Is that cos(a/2) or cos(9/2)?
sorry, it is cos(a/2)
Whew... lol.
I think it is false, If I just substitute a value in for a (like a=10). It proves false.
I have 4 more problems.. one is just like the one we just did.
sin(a+b)=sinacosb-cosasinb for all values of a and b. T/F
@luffingsails
sin(a+b) = sin(a)cos(b) + cos(a)sin(b). So false.
Sorry, my work keeps dumping me off of the site. IT security doesn't like open study. lol
oh ok, i just didn't know if you left me.. you are the first person to ever answer me on here. so your help is greatly appreciated. if cosx=2/3 and x is in quadrant 4, then sin x/2=____
No problem. Happy to help.
So, remember that cos and sine and all of those deal with right triangle (in the unit circle). So, when you have the cos (x) = 2/3 that is the same as saying adjacent side (2) over hypotenuse (3). All you have to do is solve the right triangle for the 3rd side.
3^2 = x^2 + 2^2 9 = x^2 + 4 x^2 = 9 - 4 x^2 = 5 x = sqrt(5)
x values in the fourth quadrant are the same as in the first (always positive).
when i did sqrt(5) i got 2.23 but my answer choices are -1/3 1/3 sqrt1/6 -sqrt1/6
Yes, because they are asking what the sin(x/2) is equal to. I gave you what x was equal to.
so its 1/3?
@luffingsails
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