The density of water is 1.00 h/mL at 4oC. How many water molecules are present in 2.46 mL of water at this temperature? I'm really confused how to figure this out.
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OpenStudy (somy):
what is the formula of density?
OpenStudy (anonymous):
d=m/v
OpenStudy (somy):
good so find m
OpenStudy (anonymous):
1.00= m/2.46 so you would divide 1.00 by 2.46...right?
OpenStudy (somy):
nope
\[\sf \frac{ D }{ 1 } = \frac{ m }{ V }\]
cross multiplication same as in math
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OpenStudy (somy):
D is same as D/1
OpenStudy (anonymous):
So 1.00*2.46 then?
OpenStudy (anonymous):
giving 2.46?
OpenStudy (somy):
yep
OpenStudy (somy):
so that is your mass in grams now
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OpenStudy (somy):
now you know mass and you know that talk is about H2O which means you can calculate molecular mass of H2O using periodic table
OpenStudy (somy):
thus you can find mole
OpenStudy (somy):
you know the formula of mole?
OpenStudy (anonymous):
You times the number of the element you have by the mass. So H (2*1.008) = 2.016 right?
OpenStudy (anonymous):
And O would be (1*16.00) =16.00
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OpenStudy (anonymous):
Am I wrong?
OpenStudy (somy):
yep keep goin u r right
OpenStudy (anonymous):
16.00+2.016 =18.016
OpenStudy (somy):
yep so rounding off it'll be 18
OpenStudy (anonymous):
Yes
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OpenStudy (somy):
now use mole formula and find mole
OpenStudy (anonymous):
I kinda confused on what goes where
OpenStudy (somy):
mole = mass/ molecular mass
OpenStudy (anonymous):
thanks!
OpenStudy (somy):
so now you find the moles then multiply what you got by Avogadro constant
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OpenStudy (anonymous):
mol= (2.46)/(18) =.136666
OpenStudy (anonymous):
So 8.23 x 10^22
OpenStudy (anonymous):
Or did I do it wrong?
OpenStudy (somy):
you did it right
OpenStudy (anonymous):
Thank you for the help!
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