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OpenStudy (anonymous):
basically you do this y = 7x - 6 and flip x and y so you get x = 7y -6 now ring everything but the y to the left side
OpenStudy (anonymous):
bring^*
OpenStudy (anonymous):
when you bring everything to the left your basically solving for y so yes
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
so now you got x + 6 = 7y
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OpenStudy (welshfella):
y = 7x - 6 add 6 to both sides
y + 6 = 7x
7x = y + 6
divide both sides by 7 to get x on its own
can you continue/
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
not you turn the "y" into f(x) ^-1 as the inverse and you got f(x)^-1 = (x + 6)/7 and yes thats it i just learned this in algebra 2
OpenStudy (welshfella):
write it as ( x+ 6) / 7 to avoid ambiguity
OpenStudy (anonymous):
The first step is to change the f(x) into a y. then you swith the x and the y. so it would be x=7y-6. then solve. add 6 to each side.
x+6=7y now divide 7 on both sides
x/7+6/7=y flip it
y=x/7+6/7 now change y to f^-1(x)=x/7+6/7 <-- that is the inverse
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OpenStudy (anonymous):
oops i meant f^-1(x) not f(x) ^-1 but it should be f^-1(x) = (x + 6)/7
OpenStudy (welshfella):
right
OpenStudy (anonymous):
f^-1(x) = (x + 6)/7
OpenStudy (anonymous):
they are the same thing.
OpenStudy (welshfella):
f(-1)x = (x+6)/7
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