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Mathematics 20 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

basically you do this y = 7x - 6 and flip x and y so you get x = 7y -6 now ring everything but the y to the left side

OpenStudy (anonymous):

bring^*

OpenStudy (anonymous):

when you bring everything to the left your basically solving for y so yes

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

so now you got x + 6 = 7y

OpenStudy (welshfella):

y = 7x - 6 add 6 to both sides y + 6 = 7x 7x = y + 6 divide both sides by 7 to get x on its own can you continue/

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

not you turn the "y" into f(x) ^-1 as the inverse and you got f(x)^-1 = (x + 6)/7 and yes thats it i just learned this in algebra 2

OpenStudy (welshfella):

write it as ( x+ 6) / 7 to avoid ambiguity

OpenStudy (anonymous):

The first step is to change the f(x) into a y. then you swith the x and the y. so it would be x=7y-6. then solve. add 6 to each side. x+6=7y now divide 7 on both sides x/7+6/7=y flip it y=x/7+6/7 now change y to f^-1(x)=x/7+6/7 <-- that is the inverse

OpenStudy (anonymous):

oops i meant f^-1(x) not f(x) ^-1 but it should be f^-1(x) = (x + 6)/7

OpenStudy (welshfella):

right

OpenStudy (anonymous):

f^-1(x) = (x + 6)/7

OpenStudy (anonymous):

they are the same thing.

OpenStudy (welshfella):

f(-1)x = (x+6)/7

OpenStudy (anonymous):

k :) is this algebra 2 online?

OpenStudy (anonymous):

np

OpenStudy (anonymous):

can someone help with my question?

OpenStudy (anonymous):

its about my grades ..

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