Question

Given that f(x) = 6x + 2 and g(x) = the quantity of 2x plus 4 divided by 5, solve for g(f(1)).

Answer 1

\(\bf {\color{blue}{ f(x) }} = 6x + 2\qquad g(x)=\cfrac{2x+4}{5}
\\ \quad \\
g(\quad {\color{blue}{ f(x) }}\quad )=\cfrac{2{\color{blue}{ f(x) }}+4}{5}\implies \cfrac{2{\color{blue}{ (6x+2) }}+4}{5}
\\ \quad \\
g(\quad {\color{blue}{ f({\color{brown}{ 1}}) }}\quad )=\cfrac{2{\color{blue}{ f({\color{brown}{ 1}}) }}+4}{5}\implies \cfrac{2{\color{blue}{ (6{\color{brown}{ (1)}}+2) }}+4}{5}\)

Answer 2

4

Answer 3

The answer is 4

Answer 4

Thank you for explaining it and writing it out for me. That really helped, and yes after I worked it out I got 4 as the answer.