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OpenStudy (kaederfds):
50 ml of 0.1 M sodium carbonate (s) mix with a sulfuric acid (s) taste. When measured at room temperature, calculate the volume of gas that occurs.
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OpenStudy (anonymous):
0.050 L * 0.1M=moles of CO2 (stoichometry 1 carbonate = CO2) @ STP NIST PV=nRT 1atm*V=moles of past answer*8.314 (univ gas constant)*293.15K Solve this for answer
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