Trigonometric Proof Help? \[1 + \cot (x)=\cos(x)(\sec(x)+\csc(x))\]
HI!!
Hello!
most all of this is algebra, very little is trig
Yeah, I honestly understand most of this, I just have trouble starting equations :/
we can work with the right hand side and turn it in to the left hand side in one step
what you need to know is that \(\sec(x)=\frac{1}{\cos(x)}\) and also that \(\csc(x)=\frac{1}{\sin(x)}\)
So just change the identities and solve from there?
yes, you get it right away \[\cos(x)(\sec(x)+\csc(x))=\cos(x)\left(\frac{1}{\cos(x)}+\frac{1}{\sin(x)}\right)\]
So common denomonator between 1/sinx and 1/cosx
no don't add, just multiply out on the right
Oh! Thats actually very convenient
isn't it just?
you are done right?
yup! thank you!
\[\color\magenta\heartsuit\]
Join our real-time social learning platform and learn together with your friends!