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OpenStudy (anonymous):
Trigonometric Proof Help?
\[1 + \cot (x)=\cos(x)(\sec(x)+\csc(x))\]
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OpenStudy (misty1212):
HI!!
OpenStudy (anonymous):
Hello!
OpenStudy (misty1212):
most all of this is algebra, very little is trig
OpenStudy (anonymous):
Yeah, I honestly understand most of this, I just have trouble starting equations :/
OpenStudy (misty1212):
we can work with the right hand side and turn it in to the left hand side in one step
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OpenStudy (misty1212):
what you need to know is that \(\sec(x)=\frac{1}{\cos(x)}\) and also that \(\csc(x)=\frac{1}{\sin(x)}\)
OpenStudy (anonymous):
So just change the identities and solve from there?
OpenStudy (misty1212):
yes, you get it right away
\[\cos(x)(\sec(x)+\csc(x))=\cos(x)\left(\frac{1}{\cos(x)}+\frac{1}{\sin(x)}\right)\]
OpenStudy (anonymous):
So common denomonator between 1/sinx and 1/cosx
OpenStudy (misty1212):
no don't add, just multiply out on the right
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OpenStudy (anonymous):
Oh! Thats actually very convenient
OpenStudy (misty1212):
isn't it just?
OpenStudy (misty1212):
you are done right?
OpenStudy (anonymous):
yup! thank you!
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
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