What is the probability that a randomly thrown dart that lands within the rectangle lands within a shaded region? All of the circles are congruent, and the diameter of each circle is 28 cm. A. 0.112 B. 0.196 C. 0.697 D. 0.785
HI!!
it is the ratio of the area of the circle to the area of the rectangle
a picture would be really really helpful
ugh im trying to draw it buts its hard
there we go loll
??
ok now we can do it
what are the side lenghts
you are actually told the diameter of each circle? it is 28 right (not that it matters one bit, just checking)
yess
the base of your rectangle is therefore \(28\) and the height is \(4\times 28=112\) so the area of the rectangle is ?
i get \[28\times 112=3136\] as the area
then you would subtract the area of the four circles from the area of the rectangle
each circle has radius \(14\) so area \(4*14^2\times \pi\) or about \(2463\)
theres no side lengths though thts the problem
lol no dear but we know it anyway, because the diameter is 28
|dw:1427247182374:dw|
and i get 673?
hmm no i get \[28\times 112=3136\]
for the total area that is
no 3136-2463
ooh ok i see yes
so \[\frac{673}{3136}\] for your answer
thats not an answer
lol that is because i read it wrong the second time it is not "outside of the circles" but "inside of the circles" just \[\frac{2463}{3136}\]
hmm also not quite lets do the numbers again \[\frac{4\times 14^2\times \pi}{28\times 112}\]
http://www.wolframalpha.com/input/?i=%284*14%5E2*pi%29%2F%2828*4*28%29 \[.785\]
also known as \(\frac{\pi}{4}\)
thanks!!
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