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A sample of water absorbs 50 KJ of energy when it is heated from 20 C to 60 C. What is the mass of the water?
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You need the equation: \[q=mc \Delta T\] Where q is the total heat transferred, m is the mass of the object being looked at (water in this case), c is the specific heat of that object (4.18 J/g C - a number you should know), and ∆T is the change in temperature. So, plugging in our values: \[50000=m(4.18)(60-40) \implies m =299\] There are 299 g of water.
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