Question

Trigonometric Proofs!

Answer 1

HI!!

Answer 2

Hi again!

Answer 3

more algebra?

Answer 4

Alright so basically what I have is half way through the equation I am very stuck. Ill send what I have so far

Answer 5

ok

Answer 6

so the original equation is; 1+cos (u)/ sin (u)= sin (u)/ 1-cos (u)

Answer 7

and I used the conjegate on the right side

Answer 8

to get it to; sin(1+cos (u))/1-cos^2

Answer 9

lol what was the original question??

Answer 10

oh nvm i see it

Answer 11

jeez passive aggressive much?

Answer 12

it's all yours dear

Answer 13

...

Answer 14

Yeah I think he left

Answer 15

ok lets go

Answer 16

oh lol you are done!!

Answer 17

so I now I have \[\frac{ \sin (u) (1+\cos (u)) }{ 1-\cos^2 }\]

Answer 18

I am?

Answer 19

yeah right

Answer 20

since
\[\sin^2(x)+\cos^2(x)=1\] you know \[1-\cos^2(x)=\sin^2(x)\]

Answer 21

oh yeah! ahhh I always forget to check for identities oh jeez

Answer 22

replace the denominator by \(\sin^2(x)\) and cancel a sine and go have a snack

Answer 23

yup then cancel :D

Answer 24

Thank you xD

Answer 25

\[\color\magenta\heartsuit\]

Answer 26

You still here? I have a tough one.