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(PLEASE HELP) A farmer has 1800 feet of fence and wants to enclose a rectangular field with two internal fence parallel to one side, as shown below (drawn) What are the dimensions that would maximize the area? ( I would appreciate just getting started on it and I can do the rest)
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A-area W*L W=A/L fencing 4W+2L=1800 4A/L +2L=1800 mulptiply by L 4A+2L^2 =1800L dA/dL=o for max/min and solve
dA/dL=4L-1800=0 for max L=1800/4=450 2L=900 4w=1800-900=900 w=900/4=225 so L=450 W=225
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