Question

help @hartnn

Answer 1

\(\Large\log_{9}{\frac{1}{27}}\)

I know how i would solve this using the change of base formula, but I know there's another way i can't remember. what is it?

Answer 2

write 27 as the exponent of 3

...but late you'll need change of base formula...

Answer 3

*later

Answer 4

I'm...confused. There's no 3 in the equation

Answer 5

27 = 3^3
9 = 3^2

Answer 6

\(\Large 9^x=\frac{1}{27}\rightarrow (3^2)^x=\frac{1}{3^3}\)
???

Answer 7

yes

recall
\(\Large \dfrac{1}{a^b} = a^{-b}\)

Answer 8

okay, thanks. i got it now

Answer 9

-3/2

Answer 10

yes :)

Answer 11

:)