Mat obtains a mortgage for $250,000 with the following terms: - 15 year 5/1 ARM at 6.5% with a 3/7 cap structure - - Initial monthly payments: $2,177.77 What will be the balance of the loan at the end of the initial interest rate period? I got 191,792.80
the key here is understanding the 5/1 notation. what do you recall?
and if you have covered balloon payments, thats basically what its asking
250000k^(5*12) - 2177.77(1-k^(5*12))/(1-k). k=(1+.065/12) http://www.wolframalpha.com/input/?i=250000k%5E%285*12%29+-+2177.77%281-k%5E%285*12%29%29%2F%281-k%29%2C+k%3D%281%2B.065%2F12%29 191 793 is fine
Thank you. Can you check a couple more?
if my sanity holds out sure :)
Hahah cool, thank you.
Marie has a 20 year adjustable rate mortgage with a fixed rate for the first 7 years. In the 8th year, the interest rate rises to 6.2%. the remaining balance at the end of the 7th years is $398,381.20. What is the monthly payment in the 8th year? I got 2553.73
so we pretty much want to take out a loan for the remaining balance for the remaining time period at the adjusted rate .... correct?
Bk^n(1-k)/(1-k^n) = P 398,381.20(1+.062/12)^(12(20-7))(1-(1+.062/12))/(1-(1+.062/12)^(12(20-7))) http://www.wolframalpha.com/input/?i=398%2C381.20%281%2B.062%2F12%29%5E%2812%2820-7%29%29%281-%281%2B.062%2F12%29%29%2F%281-%281%2B.062%2F12%29%5E%2812%2820-7%29%29%29 im getting something else, did you use the adjusted time frame? 20 - 7
Hmm okay is it 177711.51?
show me you work if you can
you are most likely using a formula, what is your formula?
and are there options?
i use my own formula that i develped during the class simply becuase it is sooo useful in so many applications instead of trying to recall all the other formulas for each situation.
a little workings .. we have a balance B, that gets interest ,r, added to it and then a payment ,P, removed: Bo = B B1 = Bo(1+r) - P B2 = B1(1+r) - P = Bo(1+r)^2 - P(1+r) - P B3 = B2(1+r) - P = Bo(1+r)^3 - P(1+r)^2 - P(1+r) - P .... let k clean up the compounding rate stuff to read easier Bn = Bok^n -P(1+k+k^2+...+k^(n-1)) since P represents a geometric series ... Bn = Bok^n - P(1-k^n)/(1-k) and thats the formula i use
The other options are 119333.90 and 234027.44
to determine monthly payment, then when Bn = 0, for n periods P = Bo k^n(1-k)/(1-k^n) n=12(20-7) k=1+.062/12 Bo = 398381.20
Okay so 234027.44?
im getting 3725.90
Wait, I was looking at a different question! Oh man im sorry I gave the wrong options. but now it makes sense. Im so sorry
youre options arent making any sense, ... :)
Haha I know I see that too haha.
Can you check a couple more?
has this one been satisfied? we had different solutions, do we know why?
Haha yes we do haha. Again im sorry for the different ones.
lets do another then
..... testing my sanity i spose lol
Hahah thank you :)
An investor obtains a balloon mortgage with the terms shown below: $370,00 20/5 balloon 5.1 % annual rate What is the monthly payment on this mortgage? I got $2,184.59
monthly payment is the same as a 20 year fixed rate loan P = Bo k^n (1-k)/(1-k^n) P = 370000 k^(12*20) (1-k)/(1-k^(12*20)), k=(1+.051/12) P=2462.32 it would be helpful to know how you are approaching your solutions
This one I guessed, but how did you get 2462.32?
i posted how i got the formula i use and then just used the formula ...
what are the options if any?
The other ones are 6999.32, 6481.17, 2462.32, and the first one I did.
id go with 2462 then :)
theres a monthly payment formula in your course materials, my own formula is an unsimplified version of it that just makes more sense to me personally
Oh okay cool then :) They should teach your formula. I have another question that is similar.
lets try it out
Balloon Mortgage: $300,000 25/5 balloon 6% annual rate Initial Monthly Payment $1932.90 What is the amount of the balloon payment rounded to the nearest dollar? I got $271,145
Or is it $280,559?
so the remaining balance after 5 years of payments, 5*12 = 60 payment periods B60 = Bo k^(60) -P(1-k^(60))/(1-k) B60 = 300000 k^(60) -1932.90(1-k^(60))/(1-k), k=1+.06/12 http://www.wolframalpha.com/input/?i=300000+k%5E%2860%29+-1932.90%281-k%5E%2860%29%29%2F%281-k%29%2C+k%3D1%2B.06%2F12 about 269 797 is what i get
That's one of the choices. How come its not 271145?
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