Question

what volume of oxygen, measured at room temperature and pressure is required for the complete combustion of 8.65g of H2S?

Answer 1

Start with your balanced equation.
2 H2S + 3 O2 ---> 2H2O + 2 SO2
Using stoichiometry, start with your given and convert to moles of O2.
8.65 g H2S x 1mol H2s/34.08 g H2S x 3 mol O2/2 mol H2S = 0.381 mol O2
Using the ideal gas law, PV=nRT where P= 1 atm and T = 298K,
V = 9.32 L O2

Answer 2

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