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Mathematics 19 Online
OpenStudy (anonymous):

Find, a, b, a+ b=c ab =c a,b are distinct. Please, help

OpenStudy (fibonaccichick666):

so, since you only have two equations, but thrr unknowns, you cannot actually find a and b

OpenStudy (fibonaccichick666):

but, we can find them in terms of each other. Is there any information missing?

OpenStudy (anonymous):

Nope, nothing else. Just that.

OpenStudy (fibonaccichick666):

You sure, cause there is an infinite solution set?

OpenStudy (anonymous):

ok, I need just one pair, give me, please

OpenStudy (fibonaccichick666):

pick any three numbers that make it work. there are infinite possibilities

OpenStudy (fibonaccichick666):

set c to something and solve the system

OpenStudy (anonymous):

I did, it gives me a fraction, irrational but intgers

OpenStudy (fibonaccichick666):

that's still an answer given the information you are. You can only find a or b in terms of the other.

OpenStudy (anonymous):

wonder why can't we solve it when we have 2 equations and 2 unknowns. If a, b are the roots of a quadratic equation, then the quadratic is Ax^2+ Bx + C = 0

OpenStudy (fibonaccichick666):

you have 3 unknowns

OpenStudy (fibonaccichick666):

we don't know a,b or c

OpenStudy (anonymous):

nope, a+b = -B/2A and ab= C/A that gives us -B/2 = C

OpenStudy (anonymous):

or -B = 2C, hence the quadratic becomes Ax^2 - 2Cx + C =0 with a, b are roots

OpenStudy (anonymous):

since a, b are distinct, the discriminant must be > 0

OpenStudy (anonymous):

but I don't know how to go further. brb

OpenStudy (fibonaccichick666):

no no no

OpenStudy (fibonaccichick666):

you have 3 unknowns and 2 equations. That is not how this works

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