A chemist mixes 108 g of H2O, with 186 L of NO2 at STP. How many grams of NO will be produced? The balanced equation for this reaction is:

H2O + 3 NO2 → 2 HNO3 + NO

Question

A chemist mixes 108 g of H2O, with 186 L of NO2 at STP.  How many grams of NO will be produced?  The balanced equation for this reaction is:
	
		H2O + 3 NO2  → 2 HNO3 +  NO

anonymous · Answer

I got 167 grams.  You need to take the grams of water and convert to moles of water by dividing by molecular weight (18.065)  Moles of H2O is equal to moles of NO so it is a 1 to 1 ratio.  So the number of moles of water equals the number of moles of NO.  From there you covert those moles of NO into grams of NO using the molecular weight

anonymous · Answer

Thank you very much I am completely lost on this section and this will hopefully help me understand some more