Find the non-extraneous solutions of sqrt(x+9)-5=x+4

Choices:
x=-2
x=-9 and x=-2
x=9
x=-9

Question

Find the non-extraneous solutions of sqrt(x+9)-5=x+4

Choices:
x=-2
x=-9 and x=-2
x=9
x=-9

nnesha · Answer

$$\huge\rm \sqrt{x+9} -5 = x+4$$
is it ur question ?
-5 is not under the rooot tight ?

anonymous · Answer

I would think so, given the brackets

nnesha · Answer

just wantd to confirm it 
okay 
then first add 5 both side 
and then take square both side

brynndelyn · Answer

I'm so confused on how to do this problem

nnesha · Answer

$$\huge\rm \sqrt{x+9} -5 = x+4$$
is it ur question ?
add 5 both side

brynndelyn · Answer

sqrt{x+9}=x+9

nnesha · Answer

yep now take square both side so you can cancel out square root from left side

brynndelyn · Answer

would you times each side by 2?

brynndelyn · Answer

No times by two but raise it to the 2nd power

nnesha · Answer

|dw:1427325302021:dw|
like this 
left side square and square root can cancel out
right side (x+9)^2 is same as (x+9)(x+9) 
so foil (x+9)(x+9)