Aran moved a cone-shaped pile of sand that had a height of 6 ft and a radius of 3 ft. He used all of the sand to fill a cylindrical pit with a radius of 6 ft.
How high did the sand reach in the pit?
Use 3.14 to approximate pi and express your final answer in tenths.
ft
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what is the volume of the cone?
OpenStudy (luffingsails):
So, first calculate the volume of sand in the cone. Then set that volume equal to the equation of the volume of a cylinder with radius 6 ft... then solve for the height of the cylinder.
OpenStudy (anonymous):
it doesn't say @jim_thompson5910
jimthompson5910 (jim_thompson5910):
use the formula given on the previous problem to calculate the volume of the cone
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
ok i confused my self can you set up the equation for me?
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
\[\Large V = \frac{1}{3}*\pi*r^2*h\] is the formula you need
jimthompson5910 (jim_thompson5910):
for the volume of a cone
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OpenStudy (anonymous):
what should i do with 2 radius though
jimthompson5910 (jim_thompson5910):
"Aran moved a cone-shaped pile of sand that had a height of 6 ft and a radius of 3 ft."
r = 3
h = 6
OpenStudy (anonymous):
ok so it would be 3^2*6*3.14?
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
what is that equal to
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OpenStudy (anonymous):
ok so it is equal to 169.56
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
Volume of a Cylinder
\[\Large V = \pi*r^2*h\]
OpenStudy (anonymous):
so that is correct?
jimthompson5910 (jim_thompson5910):
plug V = 169.56 into
\[\Large V = \pi*r^2*h\]
along with r = 6
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jimthompson5910 (jim_thompson5910):
then solve for h
OpenStudy (anonymous):
339.12?
OpenStudy (anonymous):
or is it 113.04
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
\[\Large V = \pi*r^2*h\]
\[\Large 169.56 = 3.14*6^2*h\]
\[\Large h = ???\]
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OpenStudy (anonymous):
idk what to do
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
you have to solve for h
jimthompson5910 (jim_thompson5910):
look at the last steps I posted above
OpenStudy (anonymous):
h=0.870
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what is 3.14*6^2 equal to?
OpenStudy (anonymous):
113.04 i kept getting that earlier but i thought it was wrong
jimthompson5910 (jim_thompson5910):
now you have
169.56 = 113.04*h
jimthompson5910 (jim_thompson5910):
divide both sides in 169.56 = 113.04*h by 113.04 to isolate h
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OpenStudy (anonymous):
SO 113.04*113.04
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
169.56 = 113.04*h
169.56/113.04 = h
h = ???
OpenStudy (anonymous):
oh ok 1.5
jimthompson5910 (jim_thompson5910):
yes
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