For the following system, if you isolated x in the first equation to use the Substitution Method, what expression would you substitute into the second equation?
-x + 2y = -6
3x + y = 8
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rishavraj (rishavraj):
from first equation
x = 6 + 2y
rishavraj (rishavraj):
on plugging the value of x in second equation
\[3(6 + 2y) + y = 8 \]
OpenStudy (anonymous):
i forgot to put answers here they are
-2y + 6
2y - 6
2y + 6
-2y - 6
OpenStudy (owlcoffee):
All you have to do, is take the expression that Rish wrote above and simplify it as much as you can.
OpenStudy (anonymous):
is that JB in your picture and im not good at simplifying equations like this lolol
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OpenStudy (owlcoffee):
No, that's my own photo...
And I think Rish already gave you the answer.
OpenStudy (anonymous):
2y+6?
rishavraj (rishavraj):
@TheAlgebraHelper man i wrote the answer in my very first comment.....:)
OpenStudy (anonymous):
so it is 2y+6 LOL
OpenStudy (anonymous):
@rishavraj help me with one more?
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rishavraj (rishavraj):
okay....
OpenStudy (anonymous):
An equation is shown below:
3 over 2 multiplied by x plus 7 over 2 equals 2 to the power of x
What is the solution to the equation?
OpenStudy (anonymous):
x = 1
x = 3
x = 5
x = 8
rishavraj (rishavraj):
u mean
\[\frac{ 3 }{ \frac{ 2x + 7 }{ 2 } } = 2^{x}\]
OpenStudy (anonymous):
umm no
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