For the following system, if you isolated x in the first equation to use the Substitution Method, what expression would you substitute into the second equation? -x + 2y = -6 3x + y = 8
from first equation x = 6 + 2y
on plugging the value of x in second equation \[3(6 + 2y) + y = 8 \]
i forgot to put answers here they are -2y + 6 2y - 6 2y + 6 -2y - 6
All you have to do, is take the expression that Rish wrote above and simplify it as much as you can.
is that JB in your picture and im not good at simplifying equations like this lolol
No, that's my own photo... And I think Rish already gave you the answer.
2y+6?
@TheAlgebraHelper man i wrote the answer in my very first comment.....:)
so it is 2y+6 LOL
@rishavraj help me with one more?
okay....
An equation is shown below: 3 over 2 multiplied by x plus 7 over 2 equals 2 to the power of x What is the solution to the equation?
x = 1 x = 3 x = 5 x = 8
u mean \[\frac{ 3 }{ \frac{ 2x + 7 }{ 2 } } = 2^{x}\]
umm no
\[3\over2\] x +\[7\over2\] = 2^x
okay then x = 3......
lol thnx
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