Question

Solve the triangle.

A = 52°, b = 10, c = 7

a ≈ 12, C ≈ 47.9, B ≈ 80.1
a ≈ 7.9, C ≈ 43.9, B ≈ 84.1
No triangles possible
a ≈ 12, C ≈ 43.9, B ≈ 84.1

Answer 1

@mathmate

Answer 2

Use the cosine rule:
\(a^2=b^2+c^2-2bc~ cos(A)\)
after that use sine rule to solve for the remaining angles:
\(\dfrac{sin(A)}{a}=\dfrac{sin(B)}{b}=\dfrac{sin(C)}{c}\)

Answer 3

@Owlcoffee

Answer 4

Mathmate is correct, all you have to do is take the equation and replace the values.

Answer 5

but i have down syndrome can u tell me the answer

Answer 6

I will not give you an answer, but I will help you out.
Let's take the cosine rule and replace the values:
\[a^2 = (10)^2 + (7)^2 -2(10)(7)Cos(52^{o})\]

Answer 7

100+49-70cos(52)

Answer 8

?

Answer 9

yes, now operate all that.

Answer 10

-52.19

Answer 11

?

Answer 12

no, it should be:
\[a^2 = 105.903\]

Answer 13

solve for "a"

Answer 14

square root of 105.903

Answer 15

10.2

Answer 16

good, that's the side "a", now to use the sine rule to find the remaining angles.

Answer 17

thats not even an answer choice

Answer 18

@TheSmartOne