How do you find the equation of a line that passes through the point (-1,-3) and is perpendicular to the line with the equation y=3/4x+11/4
first of all, a perpendicular line will have a negative reciprocal slope. can you tell me the slope of y = 3/4x + 11/4 ?? Do you know how ?
one second,
remember that in y = mx + b form, the number in the m position is the slope. So what number is in the m position in y = (3/4)x + 11/4 ?
3/4
correct...now that is the slope of the original equation...we now need the negative reciprocal of that. All that means is " flip " the slope and change the sign. For example, if the slope was 1/2, the negative reciprocal would be -2/1...see how I flipped the slope and changed the sign. So now what is the negative reciprocal of 3/4 ?
-4/3
correct.. Now we will use y = mx + b slope(m) = -4/3 (-1,-3)...x = -1 and y = -3 and since we know slope(m) and our x and y points, we need to find b, the y intercept now we sub y = mx + b -3 = -4/3(-1) + b -3 = 4/3 + b -3 - 4/3 = b -- find common denominator -9/3 - 4/3 = b -13/3 = b so your perpendicular equation is : y = -4/3x - 13/3 any questions at all ?
not anything specific, im still kind of confused by this. would you mind helping me work through a few more problems like this?
I do not mind....what else you got ?
point (1,3) that is perpendicular to the line y=2x-8
first we find slope of original equation,,,can you tell me the slope of the original equation ?
2, so would you write that as 2/1?
you can just write it as 2.....or if you want to, you can use 2/1....and we want a perpendicular line...so we need negative reciprocal of 2/1...do you know that ? Remember that negative reciprocal is when you flip the slope and change the sign. So what is the new slope we need ?
-1/2
correct....see...your getting this Now we use y = mx + b slope(m) = -1/2 (1,3)...x = 1 and y = 3 now we sub and solve for b y = mx + b 3 = -1/2(1) + b 3 = -1/2 + b 3 + 1/2 = b -- find common denominator 6/2 + 1/2 = b 7/2 = b so our perpendicular equation is : y = -1/2x + 7/2
I am so sorry....I kinda lost track of time...I have to go now but I will be back on later...sooo sorry
it's okay, thank you so much @texaschic101 !
your very welcome :)
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