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Mathematics 20 Online
OpenStudy (anonymous):

A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40 units to test for quality. The product is put through a wear-and-tear test to determine the number of days it could last. If the product has a lifespan of less than 26 days, it is considered defective. The table gives the sample data that a quality control manager collected. 39 31 38 40 29 32 33 39 35 32 32 27 30 31 27 30 29 34 36 25 30 32 38 35 40 29 32 31 26 26 32 26 30 40 32 39 37 25 29 34 Will give a medal I need help though. ASAP

OpenStudy (anonymous):

The point estimate of the mean of the sample is _____, and the point proportion of the defective units is _______. (Give your answers as decimal numbers rounded off to the nearest hundredth.) This is what were looking for

OpenStudy (kropot72):

The point estimate of the mean of the sample is calculated by finding the sum of the sample data and then dividing that sum by 40. Do you have a problem doing that?

OpenStudy (anonymous):

How would you find the defective unit?

OpenStudy (kropot72):

The question states as follows: "If the product has a lifespan of less than 26 days, it is considered defective."

OpenStudy (anonymous):

so 26?

OpenStudy (kropot72):

The data in the question gives the individual lifespans of each of the 40 units. You need to find the number of units with lifespans that are less than 26 days. Just look through the data to find them.

OpenStudy (anonymous):

So since there are 2 "25's" and them are the only two under 26 I'm guessing the answer would be 2. Sorry I never learned this and the noted in my class don't explain this.

OpenStudy (kropot72):

The point proportion of the defective units is found by dividing the number of defective units (2 units) by the total number of units in the sample (40 units).

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