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Mathematics 19 Online
OpenStudy (anonymous):

For a regular 20-sided polygon, what is the degree of rotation?

OpenStudy (anonymous):

@e.mccormick

OpenStudy (e.mccormick):

That question does not make sense to me.

OpenStudy (anonymous):

@dtan5457

OpenStudy (e.mccormick):

See, rotation is something you would have a set value for. I no of no reason why it would be associated with a polygon. To me, it just sounds incomplete.

OpenStudy (anonymous):

@e.mccormick This is what someone else said. http://openstudy.com/study#/updates/5513530ee4b0786eccf3ff4a @TheSmartOne @mathlover1011111 @ParthKohli @paki @dtan5457 Can any of you please help?

OpenStudy (rational):

I think dividing 360 by 20 gives the degree of rotation \[\large \dfrac{360}{20}\]

OpenStudy (compassionate):

^^^

OpenStudy (anonymous):

@rational @Compassionate So how would I type that into this?

OpenStudy (rational):

360/20 = ?

OpenStudy (rational):

|dw:1427346480591:dw|

OpenStudy (anonymous):

18? I would type in 18? @rational

OpenStudy (anonymous):

@rational @perl @TheSmartOne

TheSmartOne (thesmartone):

Well if you follow what they said above, the answer would be 18. But I am not sure if it is correct.

OpenStudy (anonymous):

It is, I just submitted it. :) Thanks for the help!

TheSmartOne (thesmartone):

Wohoo! :) Thanks to @rational :)

OpenStudy (perl):

what is the degree of rotation that makes the polygon congruent (in orientation)

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