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Algebra 4 Online
OpenStudy (anonymous):

Can someone help me understand this question please? I'm lost on all of it and I don't know where to start. What is the solution of -5+2x^2=-6x?

OpenStudy (jhannybean):

You want to first represent this function is general quadratic form: \(ax^2+bx+c=0\).

OpenStudy (jhannybean):

So how would you rewrite your function in order to do so?

OpenStudy (anonymous):

Do I just find like what numbers have in common or something? I havent understood functions from the start im so sorry

OpenStudy (anonymous):

[I'd read it to the end if I were you] You have to bring everything over to one side so that it equals 0 like in @Jhannybean comment. So how would you get the -6x from that side to the other? When you do that it'll equal 0. After it has to match the form she suggested (ax^2+bx-c). That means the numbers you have in the equation should line up with that format. As a hint: 2x^2 would match ax^2 BECAUSE a represents the number in front which is the 2, the x is beside it and it is squared. So when looking for bx, you're looking for a number with a x beside it. Hope this helps

OpenStudy (jhannybean):

So did you get \(2x^2+6x-5=0\)?

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