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Convert (5, (3pi)/4) to rectangular coordinates.
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\[\left(\color{red}{5}~,~\color{blue}{\frac{3\pi}{4}}\right) \implies (\color{red}{r},\color{blue}{\theta)}\]\[x=\color{red}{r}\cos(\color{blue}{\theta})\]\[y=\color{red}{r}\sin(\color{blue}{\theta})\]
You can figure it out now :)
5cos(3pi/4)=-5/√2 5sin(3pi/4)=5/√2
the answer looks like b.
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You're right.
http://www.wolframalpha.com/input/?i=5cos%283pi%2F4%29 http://www.wolframalpha.com/input/?i=5sin%283pi%2F4%29
You can simply tell by looking at the unit circle, at \(\frac{3\pi}{4}\), x is negative and y is positive. and \(\frac{3\pi}{4} \implies \frac{ \sqrt{2}}{2}\)
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