Question

Integral SOS!

Answer 1

\[\int\limits \sin \sqrt{(2x+1)}dx\]

Answer 2

it's the sin of this root

Answer 3

\[\sqrt{2x+1}=t\]

Answer 4

yeah I did that, and from there I got stuck....

Answer 5

hint:
try this substitution:
\[2x + 1 = {t^2}\]

Answer 6

oh no, why?

Answer 7

I got almost the answer, beside 2 as the coefficient

Answer 8

okay\[\sqrt{2x+1}=t ---->(2x+1)= t^{2}--->2dx/dt=2t\]

Answer 9

\[dx=tdt\]

Answer 10

we can rewrite your integral as below:

\[\int {t\sin t\;dt} \]

Answer 11

\[\int\limits tsintdt--> now \ use \\ integration \ by\ parts\]

Answer 12

LIATE<---follow this order

Answer 13

I didn't get why 2dx/dt=2t

Answer 14

oh wait