Question

ok one last integral for today

Answer 1

\[\int\limits e^(6x)*\cos(e^3x)dx\]

Answer 2

I did write e^3x=t

Answer 3

and e^6x as t^2

Answer 4

is that write? because the answer is far away from that

Answer 5

The answer is \[\frac{ 1 }{ 3 }*(e^(3x)sine^3x)+cose^(3x)\]

Answer 6

\[\large \int e^{6x}\cos(e^{3x})dx\]\[u=e^{3x}~,~ du = 3e^{3x}dx \implies e^{3x}dx = \frac{1}{3}du\]

Answer 7

You will get \[\frac{1}{3}\int u\cos(u)du\]

Answer 8

Amazing!

Answer 9

simple as that

Answer 10

Then comes integration by parts.

Answer 11

@Jhannybean thank you!!!!!

Answer 12

No problem :)