Hello! I don't usually do this but I am extremely far behind and I was wondering if someone could help explain to me how to do these things. It would mean a lot, I need to get caught up!
Okay so the problem is 30 ml of 0.10M NaOh neutralized 25.0ml of HCl. What is the concentration of the HCl? There is actually a few problems I need help with but I would like some help understanding how to do problems like this first.

Question

Hello! I don't usually do this but I am extremely far behind and I was wondering if someone could help explain to me how to do these things. It would mean a lot, I need to get caught up!
Okay so the problem is 30 ml of 0.10M NaOh neutralized 25.0ml of HCl. What is the concentration of the HCl? There is actually a few problems I need help with but I would like some help understanding how to do problems like this first.

ookawaiioo · Answer

They are both strong acid and base.

anonymous · Answer

Okay and that means...?

ookawaiioo · Answer

It means they are 1 to 1 in equivalence.

ookawaiioo · Answer

30 ml of 0.10M NaOh neutralized 25.0ml of HCl.

So thats means 0.03 L of 0.10M base, and 0.025L of HCl (acid)

ookawaiioo · Answer

Use this formula

Molarity of base* Liter of base = Molarity of acid* liter of acid

anonymous · Answer

So would it be 0.10 * 0.03 = ? * 0.025 
I am still kind of lost I apologize

ookawaiioo · Answer

Yes thats the equation

anonymous · Answer

So in order to find it out I would do the 0.10 * 0.03 which equals 0.003 and would I then divide that by 0.025?

ookawaiioo · Answer

yes

anonymous · Answer

Thank you so much for the help!