Question

A baseball diamond is a square 90 feet on each side. Suppose the pitcher is in the exact middle of the diamond and the batter hits a ball to the first baseman. The pitcher needs to run to first base (to receive the throw from the first baseman) before the batter can get there. How much shorter is the pitcher's run to the base than the batter's?

Answer 1

@Gummibear127

Answer 2

I know I need to use the Pythagorean theorem, just not how

Answer 3

Oh lol i just learned that theorem give me a second

Answer 4

Ok, this is an extra credit problem, so its harder (at least for me it is :P)

Answer 5

*it's

Answer 6

what are the options?

Answer 7

There are not any options, its a show-your-work type of question

Answer 8

45 ft.?

Answer 9

That is what I was thinking too

Answer 10

because it's about halfway inbetween each base

Answer 11

hmm... don't I have to do a^2+b^2=c^2 and all that stuff?

Answer 12

tha'ts what I was thinking

Answer 13

but yes you do

Answer 14

so you just divide 90 by 2

Answer 15

pretty much

Answer 16

so 90^2+90^2=90^2

Answer 17

I'm almost positive that isn't the way to do it....

Answer 18

ehh it was just an educated guess

Answer 19

Ok, I will wait for someone who like if VERY confident and knows the answer exactly or can teach me it. Thanks though

Answer 20

Im not really good with this maybe @iGreen can help

Answer 21

*is

Answer 22

Ok

Answer 23

alright

Answer 24

@perl

Answer 25

Can anyone help me out???

Answer 26

@amistre64