A baseball diamond is a square 90 feet on each side. Suppose the pitcher is in the exact middle of the diamond and the batter hits a ball to the first baseman. The pitcher needs to run to first base (to receive the throw from the first baseman) before the batter can get there. How much shorter is the pitcher's run to the base than the batter's?
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@perl @igreen I need help!
Thanks for coming :D
Hello? Are you here? Most people just said 45, but I thought it would have been more complicated
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you can use pythagorean theorem
90^2+90^2= h^2?
I mean c^2
90 is the hypotenuse here
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\[\sqrt90^2+90^2=c\]
so 90/2?
$$ \Large{ x^2 + x^2 = 90^2 \\ 2x^2 = 90^2 \\~\\ \\ x^2 = \frac{90^2}{2} \\~\\ \\ x = \sqrt{\frac{90^2}{2}} \\~\\ \\ x = \frac{\sqrt{90^2}}{\sqrt2 } \\~\\ \\ x = \frac{90}{\sqrt2 } } $$
You can't get the square root of 2...
you can rationalize the denominator
$$ \Large{ x^2 + x^2 = 90^2 \\ 2x^2 = 90^2 \\~\\ \\ x^2 = \frac{90^2}{2} \\~\\ \\ x = \sqrt{\frac{90^2}{2}} \\~\\ \\ x = \frac{\sqrt{90^2}}{\sqrt2 } \\~\\ x = \frac{90}{\sqrt2 } \\~\\ x = \frac{90}{\sqrt2 }\cdot \color{red}{\frac{\sqrt2 }{\sqrt2}} \\~\\ x = \frac{90 \cdot \sqrt2 }{2} \\~\\ x = \color{blue}{45\cdot \sqrt 2 } } $$
so 45 was it?
45 times square root 2
which is about 63.6396 in decimal
ok, thanks :D
but the question asks, how much shorter
$$ \Large 90 - 45 \sqrt 2$$
=27ish?
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