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Calculate l-10+24il.
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Absolute value of imaginary numbers: |a + bi| = \(\sqrt{a^2+b^2}\)
@StudyGurl14 do I plug that into the formula?
Yeah
So, you have |-10 + 24i|
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that means -10 = a, and 24 =b
square root -10+24 = square root 14
remeber to square the -10 adn 24 (see formula ^)
No, the formula is \(\large\sqrt{a^2+b^2}\) So...\(\large\sqrt{(-10^2+(24)^2}\)
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2 square root 119
yeah
@StudyGurl14 that's the answer?
what about the i?
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the lines on the l-10+24il signify magnitude right?
yeah
That's the answer, and yes, that's the magnitude
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