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Mathematics 13 Online
OpenStudy (kj4uts):

Calculate l-10+24il.

OpenStudy (kj4uts):

OpenStudy (studygurl14):

Absolute value of imaginary numbers: |a + bi| = \(\sqrt{a^2+b^2}\)

OpenStudy (kj4uts):

@StudyGurl14 do I plug that into the formula?

OpenStudy (studygurl14):

Yeah

OpenStudy (studygurl14):

So, you have |-10 + 24i|

OpenStudy (studygurl14):

that means -10 = a, and 24 =b

OpenStudy (kj4uts):

square root -10+24 = square root 14

OpenStudy (studygurl14):

remeber to square the -10 adn 24 (see formula ^)

OpenStudy (studygurl14):

No, the formula is \(\large\sqrt{a^2+b^2}\) So...\(\large\sqrt{(-10^2+(24)^2}\)

OpenStudy (kj4uts):

2 square root 119

OpenStudy (studygurl14):

yeah

OpenStudy (kj4uts):

@StudyGurl14 that's the answer?

OpenStudy (kj4uts):

what about the i?

OpenStudy (kj4uts):

the lines on the l-10+24il signify magnitude right?

OpenStudy (studygurl14):

yeah

OpenStudy (studygurl14):

That's the answer, and yes, that's the magnitude

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