Question

Will give medal and become fan!!! PLEASE HELP!!
Given the arithmetic sequence an = 4 - 3(n - 1), what is the domain for n?
Answer Choices
All integers where n ≥ 1
All integers where n ≥ 4
All integers where n > 1
All integers where n ≤ 4

Answer 1

@dmndlife24 @fallenangelorchid @Freedom101 @chycora @radar @robtobey @JFraser

Answer 2

@iGreen @amorfide @Hami1017 @Asad786 @essence.m

Answer 3

you know that the starting term is 4, since the formula is
an=a+(n-1)d

so starting term is 4
difference is -3
n is the term number
if you want the first term let n=1
so if you want the second term let n=2
third term n=3

you know that the domain is all possible values you can input into a function
and range is all possible outcomes of a function

Answer 4

given this information can you give the question a go yourself?

Answer 5

Hold up

Answer 6

That means an=1 or -3?

Answer 7

@amorfide I think It is A...

Answer 8

your answer choice is correct but I do not think you understand why

Answer 9

Because I got 1 at first and it just kept getting smaller like negative is that why?

Answer 10

okay so
the regular expression for an arithmetic sequence is
an=a+(n-1)d

a is the first term of the sequenc
n is the term number you want to find
and d is the difference

so you know that your variable is n, this means our domain is all possible n values we can input into this function

so we know that we can not have negative amount of terms, since you can not have -3 numbers in a sequence (if that makes sense) you can only have a possible number of terms in a sequence

if we substitute in 1 we get our first term
therefore you can only input any number that is equal to or greater than 1

Answer 11

Can you help me with this one. Ill try it first Given the geometric sequence where a1 = 3 and the common ratio is -1, what is the domain for n? answer choicesAll integers where n ≥ 0
All integers where ≤ 0
All integers where n ≥ 1
All integers where n ≤ 1

Answer 12

you give it a go

Answer 13

your right @amorfide ... I need help

Answer 14

idk why it is screwed up

Answer 15

well you already know that n is the term number
you have to have a positive amount of terms in a sequence

knowing that the regular expression is

\[a _{n}=ar^{n-1}\]

where a is the first term, r is the ratio and n is the term number

Answer 16

does this help?

Answer 17

Do you always have to have a positive?

Answer 18

if I have a sequence of numbers

I can not have a negative amount of numbers in my sequence

1,2,3

-2,-3,-4

there are 3 amounts in both sequences, no matter what I can't get a negative n

Answer 19

I have the formula and I know how to plug in the formulas but i dont know what to put in and what it will prove?

Answer 20

OHHHHHH thanks that makes sinse

Answer 21

so what number n do you use to get the first term of the geometric sequence

Answer 22

So it is just a count of the number...

Answer 23

1?

Answer 24

n is the term number
not the amount of terms

so yes you are correct you start at n=1

Answer 25

numbers* sorry

Answer 26

so, now you know n starts with the value of 1 to get the first term

Answer 27

you should know you can let n=2
n=3
until you can not count anymore

Answer 28

therefore n is greater than or equal to 1

Answer 29

so your domain is all possible input values of n

Answer 30

from 1 to infinite

Answer 31

Is that kind of how it is with all questions like this?

Answer 32

Thanks so much!

Answer 33

Your a bro

Answer 34

Do you get paid doing this?

Answer 35

yeah let's say I had a function

f(x)=2x+3

domain is all possible x values I can put into this function
so I can put all real numbers into this function, ranging from negative infinite to infinite

Answer 36

simple as that lol
no I do not get paid

Answer 37

Just for fun