Write the expression as a single logarithm. Identify any properties used.
3 log4 x + 2 log4 x
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OpenStudy (anonymous):
@freckles can you help me again
OpenStudy (freckles):
\[\text{ power rule } r \log_a(x)=\log_a(x^r) \\ \text{ product rule } \log_a(cd)=\log_a(c)+\log_a(d)\]
OpenStudy (freckles):
these are the two rules you will need
OpenStudy (freckles):
for the particular expression
OpenStudy (freckles):
so the first rule says you can do something with the 3 in front of log_4 (x)
and the 2 in front of log_4(x)
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OpenStudy (freckles):
well there is another way to look at the problem
you do have like terms
OpenStudy (anonymous):
So log4 x^3+ log4 x^2
OpenStudy (freckles):
cool
OpenStudy (freckles):
now use product rule
OpenStudy (freckles):
\[\log_a(c)+\log_a(d)=\log_a(c \cdot d)\]
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OpenStudy (anonymous):
log4(x^3*x^2) ?
OpenStudy (freckles):
cool
OpenStudy (freckles):
\[\log_4(x^3 \cdot x^2) \\ \log_4(x^{3+2})\]
OpenStudy (anonymous):
Thats all I have to do?
OpenStudy (freckles):
well do 3+2 and then you are done
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OpenStudy (anonymous):
Ok. Thank you again lol
OpenStudy (freckles):
\[\log_4(x^5)\]
OpenStudy (freckles):
there is another way to have looked at this problem
OpenStudy (freckles):
you do have like terms above
3u+2u=5u
so you had
\[3\log_4(x)+2\log_4(x)=(3+2)\log_4(x)=5 \log_4(x) \\ \text{ which this should be fine as an answer too } \\ \text{ or using power rule you have } = \log_4(x^5) \\ \text{ either answer should be fine }\]
OpenStudy (freckles):
anyways be sure to mention the rules you used in your answer
because i see your teacher has that as instruction in this problem
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