A ball has a diameter of 9 in. It consists of 2 parts. The inside is a spherical core with a diameter of 6 in. Surrounding the core is a layer of polyurethane.
What is the volume of the polyurethane?
Use 3.14 to approximate pi and express your answer in hundredths.
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OpenStudy (freckles):
you will have to find the difference of the volume of the whole ball minus the volume of just the core
to find the outer layer volume
OpenStudy (freckles):
use the sphere volume twice
OpenStudy (anonymous):
oh ok
OpenStudy (freckles):
try this one
and put your answer here
if it isn't what I have we will go over this slowly like the last
OpenStudy (anonymous):
radius 6 i got 113.04
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OpenStudy (anonymous):
i mean diameter 6
OpenStudy (freckles):
wait
OpenStudy (freckles):
radius is not 6
OpenStudy (freckles):
diameter is 9
radius is 9/2
OpenStudy (anonymous):
i know it is 3
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OpenStudy (freckles):
well for the core 3 is right for the radius
OpenStudy (anonymous):
i got for diameter 9 the radius 4.5 and got the volume of 381.51cm
OpenStudy (anonymous):
@freckles are you there
OpenStudy (anonymous):
so what do i do now
OpenStudy (freckles):
omg i keep writting 2 instead of 3
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OpenStudy (anonymous):
its alright
OpenStudy (anonymous):
i dont get the last part in the bottom
OpenStudy (freckles):
you still need to find the volume of the smaller ball inside the big ball
OpenStudy (anonymous):
do i subtract the bigger number from the smaller number
OpenStudy (freckles):
the smaller from the bigger
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OpenStudy (freckles):
doing the opposite will give you a negative number
OpenStudy (anonymous):
oh ok so 113.04 - 381.51
OpenStudy (freckles):
no take the smaller from the bigger lol
\[\frac{4}{3} \cdot 3.14 \cdot (\frac{9}{2})^3-\frac{4}{3} \cdot 3.14 \cdot (\frac{6}{2})^3\\ 381.51-\frac{4}{3} \cdot 3.14 \cdot (\frac{6}{2})^3 \\ 381.51 -113.04\]
OpenStudy (anonymous):
sorry i meant the other way around
OpenStudy (anonymous):
268.47cm is what i got
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OpenStudy (freckles):
great job
except the units part
cm^3 :)
OpenStudy (anonymous):
ok one more please
OpenStudy (freckles):
one more will have to wait after i run a quick errand
OpenStudy (freckles):
it will be kinda quick
OpenStudy (anonymous):
ok then thank you for your help anyway
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OpenStudy (freckles):
i'm back
OpenStudy (anonymous):
ok do i start a new one or right here
OpenStudy (freckles):
I don't care
one last question right?
OpenStudy (freckles):
if it is one question I will work on it with you
OpenStudy (anonymous):
ya last question
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OpenStudy (anonymous):
A can of spaghetti has a diameter of 12 cm and a height of 16 cm. The can contains spherical meatballs, each with a radius of 3 cm, that take up 25% of the volume.
How many meatballs are in the can?
Use 3.14 to approximate pi and express your answer as a whole number.
OpenStudy (freckles):
now i'm hungry
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
lol
OpenStudy (freckles):
the spaghetti made me hungry :p
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OpenStudy (freckles):
anyways
OpenStudy (freckles):
ok let's go ahead and find the volume of the can
OpenStudy (anonymous):
its a sphere volume right
OpenStudy (freckles):
well a can is a cyclinder
OpenStudy (anonymous):
oh ya my bad
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OpenStudy (freckles):
we will use sphere formula for the meatballs though
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i got 1809.56
OpenStudy (freckles):
one sec checking
OpenStudy (freckles):
what did you do to get that
(it is close to what I have but not exact)
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OpenStudy (anonymous):
ya what did you get
OpenStudy (freckles):
1808.64
OpenStudy (freckles):
see kinda close
OpenStudy (anonymous):
i did it on google
OpenStudy (anonymous):
i just put volume of a cylinder and type in the radius and height
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OpenStudy (freckles):
oh i see what you did
OpenStudy (freckles):
you put pi instead of 3.14
OpenStudy (freckles):
and it wants us to use 3.14 instead of pi
but in reality your answer is more closer than mine
OpenStudy (freckles):
but we should do what the instructions want
OpenStudy (anonymous):
ok so your right. right
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OpenStudy (anonymous):
1808.64
OpenStudy (freckles):
yah
OpenStudy (anonymous):
ok so what now
OpenStudy (freckles):
now try to find the volume of a single meatball :)
OpenStudy (anonymous):
what formula do i use
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OpenStudy (freckles):
they describe meatballs as if they were spheres
so you used the formula for volume of a sphere
OpenStudy (anonymous):
so it is 113.1
OpenStudy (freckles):
113.04 is what I have
OpenStudy (anonymous):
what so whos right
OpenStudy (freckles):
so pretend there are n meatballs
so the volume that the meatballs make up is
n*113.04
and we are given that n*113.04 is .25 of the volume we found from the cylinder
that is:
\[n \cdot 113.05=.25 \cdot 1808.64\]
now we solve for n
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OpenStudy (freckles):
\[n \cdot 113.04=.25 \cdot 1808.64\]*
OpenStudy (freckles):
well I did 4/3*3.14*3^3
OpenStudy (freckles):
what did you do?
OpenStudy (anonymous):
same thing. on the step you told me to do i dont get it
OpenStudy (freckles):
the equation involving solve for n?
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OpenStudy (freckles):
we are given that a number of meatballs is 25% of the can's volume
OpenStudy (freckles):
I just translated that into a mathematical equation
OpenStudy (freckles):
i called the number n
n*volume of meatball=.25*volume of can
OpenStudy (freckles):
divide both sides by volume of meatball
to solve for n
OpenStudy (anonymous):
so whats the equation again
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OpenStudy (freckles):
\[n=\frac{.25 \cdot 1808.64}{113.04}\]
OpenStudy (anonymous):
i got 4
OpenStudy (freckles):
sounds great
OpenStudy (freckles):
that sounds like a horrible spaghetti an
because I prefer a lot of meatballs
OpenStudy (anonymous):
Thank you for all your help.
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OpenStudy (freckles):
can*
OpenStudy (anonymous):
the answer is 4 right
OpenStudy (freckles):
yes that is what we came up with
there are 4 meatballs