Will give medal. A company distributes free candies to all the students of x schools. Each school has (x + 1) classes. The number of students in each class is 3 more than the number of classes in each school. Each student is given 4 candies. The equation is 4(x+4)(x+1)x How can you calculate the total number of students in each school?

Question

anonymous · Answer

@freckles @Nnesha @jdoe0001

anonymous · Answer

I erased what I was writing to better explain it, but I'd definitely not going to now.

anonymous · Answer

im trying to help :)

anonymous · Answer

and 1 thank you for that

anonymous · Answer

The equation you give--what does that equal?

anonymous · Answer

As in, what is that the equation for?

anonymous · Answer

finding the number of candles distributed.

anonymous · Answer

each kid gets 4 candles so divide that equation by 4 1 guess...

anonymous · Answer

sorry if it keeps looking like 1'm not here, firefox continues to prove its uselessness.

anonymous · Answer

hmmm  i believe you must distribute

anonymous · Answer

:3 but what do i know xD

anonymous · Answer

1 guess if you took away the 4 from the front of the equation it would apply better...

anonymous · Answer

Each student is given 4 candies. The equation is 4(x+4)(x+1)x  (4x+16)(x+1)

anonymous · Answer

$$Candies=4x^{3}+20x^{2}+16x$$

anonymous · Answer

im not sure much of to the third power chrismoon
im

anonymous · Answer

(x+4)(x+1) gives you x^2+5x+4
That's multiplied by 4x

anonymous · Answer

1s it even possible to find the number of candles?

anonymous · Answer

That's what I'm thinking, I don't see any info given to help you find how many candies total the company gives or what the 4 candies per student tells you.

anonymous · Answer

ok i have the answer

anonymous · Answer

okay...

anonymous · Answer

well im not sure if it is the answer but im so much 90% sure $$Candies = 4x^2 +20x +16$$

anonymous · Answer

:D

anonymous · Answer

but we're trying to find the number of students

anonymous · Answer

144

anonymous · Answer

How did you get that?

anonymous · Answer

http://www.wolframalpha.com/input/?i=4x%5E2+%2B+20x+%2B+16

anonymous · Answer

haha wow

anonymous · Answer

those are the closest answers u can get :)

anonymous · Answer

awesome thanks

anonymous · Answer

do you think you could look at one more for me?

anonymous · Answer

sure

anonymous · Answer

gimme a second there's a lot of exponents

anonymous · Answer

ok

anonymous · Answer

Divide$$(8x ^{4}y ^{3}+4x ^{3}y ^{2}-2x^2y-12x^2y^4)$$ by $$-2x^2y$$

anonymous · Answer

wow

anonymous · Answer

1 think it's $$-4x^2y^2-2xy+6y^3$$ but 1'm not sure

anonymous · Answer

Factor out -2(x^2)(y) from the numerator then cancel with the denominator.

anonymous · Answer

1 did

anonymous · Answer

Which looks like what you did, but when you factor out the -2x^2 y from inside, you need to keep a +1 inside the parenthesis.

anonymous · Answer

wait one sec i'll tell u the answer

anonymous · Answer

You got it right, just add the +1 you forgot.

anonymous · Answer

where would it be in the equation?

anonymous · Answer

3rd

anonymous · Answer

before the 6y^3

anonymous · Answer

or after, doesn't really matter. addition is commutative (you can rearrange them)

anonymous · Answer

6y^3-4x^2y^2-2xy+1

anonymous · Answer

associative*, not commutative

anonymous · Answer

that should be the answer bloofoffiction

anonymous · Answer

Okay. Thank you guys, you've been a huge help, both of you.

anonymous · Answer

Np