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Algebra 9 Online
OpenStudy (narissa):

i need help with cube roots please

OpenStudy (studygurl14):

I'm here

OpenStudy (narissa):

OpenStudy (narissa):

@StudyGurl14

OpenStudy (astrophysics):

\[\sqrt[3]{108} \implies 108^{1/3}\]

OpenStudy (studygurl14):

the first step would be to factor 108 to find something you can simplify in some way.

OpenStudy (studygurl14):

Automatically, you can see that 108 is divisble by 4, because the last two digits is 08, and 8 is dividible by 4.

OpenStudy (studygurl14):

So, what is 108 / 4?

OpenStudy (jhannybean):

\[\sqrt[3]{108} = (108)^{1/3} = (12 \cdot 9)^{1/3} = (4 \cdot 3 \cdot 3^2)^{1/3} = (4 \cdot 3^3)^{1/3}\]

OpenStudy (narissa):

27

OpenStudy (astrophysics):

That's what it's implying, so to deal with such a problem, we'll stick with inside the "root" \\[\sqrt[3]{108} \implies \sqrt[3]{3^3 \times 4} \implies 3\sqrt[3]{4}\]

OpenStudy (jhannybean):

Now just distribute the power. \[(4)^{1/3} \cdot (3^3)^{1/3}\]

OpenStudy (narissa):

what do i do with the first numbers in the answers?

OpenStudy (jhannybean):

\[3^{3 \cdot 1/3} = 3\]

OpenStudy (jhannybean):

Since you cannot reduce 4 inside a cube root (mainly because it's a perfect square and not a perfect cube) you leave it under the cube root.

OpenStudy (narissa):

so does that mean its b?

OpenStudy (astrophysics):

haha, yes :)

OpenStudy (jhannybean):

Precisely.

OpenStudy (narissa):

thanks what does f.b mean

OpenStudy (astrophysics):

Haha, I was just saying fb, as in facebook because people always do like for like and crap like that :P

OpenStudy (narissa):

lol i dont understand what ur saying

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