i need help with cube roots please
I'm here
@StudyGurl14
\[\sqrt[3]{108} \implies 108^{1/3}\]
the first step would be to factor 108 to find something you can simplify in some way.
Automatically, you can see that 108 is divisble by 4, because the last two digits is 08, and 8 is dividible by 4.
So, what is 108 / 4?
\[\sqrt[3]{108} = (108)^{1/3} = (12 \cdot 9)^{1/3} = (4 \cdot 3 \cdot 3^2)^{1/3} = (4 \cdot 3^3)^{1/3}\]
27
That's what it's implying, so to deal with such a problem, we'll stick with inside the "root" \\[\sqrt[3]{108} \implies \sqrt[3]{3^3 \times 4} \implies 3\sqrt[3]{4}\]
Now just distribute the power. \[(4)^{1/3} \cdot (3^3)^{1/3}\]
what do i do with the first numbers in the answers?
\[3^{3 \cdot 1/3} = 3\]
Since you cannot reduce 4 inside a cube root (mainly because it's a perfect square and not a perfect cube) you leave it under the cube root.
so does that mean its b?
haha, yes :)
Precisely.
thanks what does f.b mean
Haha, I was just saying fb, as in facebook because people always do like for like and crap like that :P
lol i dont understand what ur saying
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