Question

@amistre64 @zepdrix @paki I need help with Complex Fractions

Answer 1

I need to write two complex fractions that simplify to
\[\frac{ x-2 }{ x+4 }\]

Answer 2

x or x^2 ?

Answer 3

x

Answer 4

multiply top and bottom by a complex number perhaps? or a conjugate ... but a conjugate tends to get us x^2

Answer 5

where \(f(x)\neq 0\)\[\frac{f(x)(x-2)}{f(x)(x+4)}= \frac{x-2}{x+4}\]

Answer 6

yeh i was thinking along those lines :)

Answer 7

Okay so that works. I don't necessarily need functions for this. I need any complex fraction that is similar to this one

\[\frac{ \frac{ 2 }{ x } -\frac{ 3 }{ y } }{ \frac{ -5 }{ x } + \frac{ 7 }{ y } }\]

Answer 8

complex, i was thinking you needed a complex number like 2+3i .... you simply want some complicated fractional working instead.

Answer 9

Yeah unfortunately. That's how my textbook goes by

Answer 10

divide top and bottom by say: xy, then split fractions ... an idea

Answer 11

Okay

Answer 12

\[\frac{ \frac{x-2}{xy} }{ \frac{x+4 }{xy}}\]
\[\frac{ \frac{x}{xy}-\frac{2}{xy} }{ \frac{x}{xy}+\frac{4 }{xy}}\]
\[\frac{ \frac{1}{y}-\frac{2}{xy} }{ \frac{1}{y}+\frac{4 }{xy}}\]
etc ...

Answer 13

or multiply
\[\frac{ \frac{ 2 }{ x } -\frac{ 3 }{ y } }{ \frac{ -5 }{ x } + \frac{ 7 }{ y } }= \frac{( \frac{ 2 }{ x } -\frac{ 3 }{ y } )\times xy}{ (\frac{ -5 }{ x } + \frac{ 7 }{ y } )\times xy}=\]

Answer 14

Oh, okay. Now, I understand. Thank you both!

Answer 15

good luck