Ask your own question, for FREE!
Chemistry 11 Online
OpenStudy (anonymous):

Using a balanced equation for the synthesis reaction between Sodium metal and Chlorine gas: Calculate how many grams of Salt may be produced from a 5.00 gram sample of solid sodium metal when combined with unlimited Chlorine gas.

OpenStudy (anonymous):

Does this have something to do with the factory label method? I'm just kind of confused as to how it all goes together.

OpenStudy (anonymous):

2Na + Cl2 -->2NaCl 5 gram of sodium / Na weight (I think its 23 g/mol) = moles of sodium. 2 moles of sodium yields 2 moles of salt so, the ratio is equal. so the quantity you get diving 5 g/Na weight is the answer

OpenStudy (anonymous):

does the chlorine come into play anywhere, though?

OpenStudy (anonymous):

or no since there's an unlimited amount?

OpenStudy (anonymous):

Since there is an unlimited amount, the chlorine isnt the limiting reagent, so it doesnt matter the quantity used to make the salt, but if you want to learn you would actually need half the moles of chlorine to make the same amount of salt. so if you have 1 mole of Na, youll need to have only 0.5 mol of Cl2

OpenStudy (anonymous):

|dw:1427441507611:dw| So that makes sense? Then the answer would only be .22 mol then I'd have to convert that into grams?

OpenStudy (anonymous):

Or is that already in grams? I apologize, chemistry is not my best subject.

OpenStudy (anonymous):

\[5 g Na (1 mol/23 g) = 0.2174 mol Na\] then 0.2174 mol Na (2 NaCl/2 Na [from the balancing])=0.2174 mol NaCl then 0.2174 * (23 + 35.45 (i think this is the weight of Cl))=grams of NaCl

OpenStudy (anonymous):

the equation in the midle is the stoichometry balance, or the ratios, wich in this case are the same, but dont forget to do that because you can easily get a mistake in there

OpenStudy (anonymous):

you did your 3's rule wrong, the 23 goes on the other side (the left)

OpenStudy (anonymous):

Okay, I think I get it. Thank you :)

OpenStudy (anonymous):

Sure :D, need anything else? cause im going to sleep shortly

OpenStudy (anonymous):

haha I probably will eventually, but I think I'm okay for now and I'm going to sleep as soon as I finish this god awful equation. I'm going to become your fan or whatever they call it on here, though, if it's okay. I may need some help in the near future haha :)

OpenStudy (anonymous):

k night

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!