Question

integral question

Answer 1

\[\int\limits_{}^{} 2r* \sin(2r)\]

Answer 2

what do you think about this one?

Answer 3

We have to use integration by parts

Answer 4

that's correct

Answer 5

\[\int\limits_{}^{}usin(u)\]

Answer 6

u being 2r

Answer 7

no need for unnecessary substitution.

Answer 8

??

Answer 9

oh ok

Answer 10

no need to substitute it. just take the 2 out.

Answer 11

is the antiderivative of sin(2r) is -1/2(cos(2r))?

Answer 12

yes!

Answer 13

okay

Answer 14

r/2 * cos(2r) + cos(2r)/2

Answer 15

something went wrong >.<

Answer 16

\[\int 2r\sin(2r)dr = -r\cos(2r) -\int -\cos(2r)dr\]

Answer 17

wait let's break this apart

Answer 18

uv= r * (-1/2) cos(2r)?

Answer 19

There's a 2 too.

Answer 20

how?

Answer 21

where?

Answer 22

2r sin(2r)

Answer 23

OH

Answer 24

oops

Answer 25

u = 2r
dv = sin(2r) dr

Answer 26

Thank you