Question

Differential Equation y'=3y^(2/3)
and y(2)=0

Answer 1

\[y'=3\sqrt[3]{y^2}\]

Answer 2

\[y(2)=0\]

Answer 3

the final answer is \[y=(x-2)^3\]

Answer 4

if you guys could help me out with it it will literally

Answer 5

make my day*

Answer 6

Have you considered the antiderivative? \(y = 3 \dfrac{y^{5/3}}{5/3} + C\)

Simplify first, of course.

Answer 7

wow

Answer 8

is it the same? can you explain?

Answer 9

@shereenkhan ?

Answer 10

nah @tkhunny I don't think that's the way tbh

Answer 11

what do you have to do?

Answer 12

to get y
need to integrate y'

Answer 13

are you sure?

Answer 14

wby not just writing instead of y'=dy/dx?