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Given the expression (1 + 2i)2, perform the indicated operation and write the answer in the form a + bi. −1 − 2i −3 + 4i −4 − 4i −3 − 4i
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yes they are.
@iGreen help pls
(1 + 2i)(1 + 2i) = (1 + 2i) + 2i(1 + 2i) can you continue?
distribute 2i over (1 + 2i)
= 1 + 21 + 2i*1 + 2i*2i = ?
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8 sorry that's 1 + 2i + 2i*1 + 2i*2i
what is 2i* 2i?
no its 4i^2 do you know what the definition of i is?
when you manipulate it algebraically just treat it as a variable like x or y.
its an imaginary number and equal to sqrt(-1) so i^2 = sqrt(-1) squared = -4 so 4i^2 = -4
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gotta go right now
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