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Can someone help me understand this? Calculate the pH of a solution with a concentration 4.2 * 10^-5 molar OH-
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There are different ways of doing this. You can find the concentration of the hydronium ion. \[\color{green}{K_w = [H^{+}][OH^{-}]}\] Then,\[\color{green}{pH = - \log [H^+]}\] Another approach would be to find pOH first.
Like this? \[[1.0\times10^{-14}][4.2\times10^{-5}]\]
@ghuczek
Divide Kw by the concentration of the hydroxide ion to find the concentration of the hydronium ion.
What should the answer look like? I'm getting 2.38
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Pardon me, 2.38 * 10^-10
Alright man, I got it! Thanks! answer is 9.62
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