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If f(x) = (1/5)^x and g(x) = log(25)(x), find g(f(-1)) *With Attachment*
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nice and slow here
what is \[\left(\frac{1}{5}\right)^{-1}\]??
5
ok good so finally what is \[\log_{25}(5)\]?
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if that is not clear i can explain it
Um I think it is .5 or 1/2
bingo
Woo
\[\log_{25}(5)\] solve \[25^y=5\] and since \[\sqrt{25}=5\\ 25^{\frac{1}{2}}=5\]you get \[\frac{1}{2}\]
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\[\log_{25} (5)=x\]\[25^x=5\]\[5^{2x}=5\]\[2x=1\]\[x=\frac{1}{2}\]
Thank you both!
there is more than one way to skin a mule
oh haha okay
Sounds excruciatingly painful.
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Indeed
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